30=-16x^2+98x+12

Solution for 30=-16x^2+98x+12 equation:

30=-16x^2+98x+12

We move all terms to the left:

30-(-16x^2+98x+12)=0

We get rid of parentheses

16x^2-98x-12+30=0

We add all the numbers together, and all the variables

16x^2-98x+18=0

a = 16; b = -98; c = +18;
Δ = b2-4ac
Δ = -982-4·16·18
Δ = 8452
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8452}=\sqrt{4*2113}=\sqrt{4}*\sqrt{2113}=2\sqrt{2113}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-2\sqrt{2113}}{2*16}=\frac{98-2\sqrt{2113}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+2\sqrt{2113}}{2*16}=\frac{98+2\sqrt{2113}}{32}
$